RE: [PHP] BUG: require_once() or die(); = fatal error

Hmm... Well Rasmus, I do see your point, however it still seems to me it 'should' at least compile and work as I expect it to. My way, the logic is that the file *is* 'required' (whereas I view 'include' files as optional), and I want to exit the program with a graceful message instead of the fatal error (which doesn't really doesn't tell me what the problem is -- "Failed opening required '1'" doesn't mean anything to me or the user) that is shown. My intent was to put a @require_once() so that I could do just that. Especially since I'm running my script on the command line, and your stock fatal error message uses HTML tags. Not a critical bug or a show stopper, but I do still feel it is a bug. > -----Original Message----- > From: Rasmus Lerdorf [mailto:rasmus@php.net] > Sent: Wednesday, November 26, 2003 8:55 PM > To: Daevid Vincent > Cc: php-general@lists.php.net > Subject: Re: [PHP] BUG: require_once() or die(); = fatal error > > This code doesn't make much sense. By definition, if require > cannot open > a file it throws a fatal error, so you would never hit the "or" case > anyway. Hence there is no return code from require and you > can't write > code like this. If you want to test the return code you need to use > 'include' instead. > > -Rasmus > > On Wed, 26 Nov 2003, Daevid Vincent wrote: > > > Using PHP 4.2.2 on Linux RH8: > > > > In a PHP script run from command line, > > > > require_once("gibberator_data.php") or die("No Data > file found\n"); > > > > Causes: > > > > [root@locutus gibberator]# ./gibberator.php > > <br /> > > <b>Fatal error</b>: Failed opening required '1' > > (include_path='.:/php/includes;/usr/share/phpwebtools') in > > <b>/home/gibberator/gibberator.php</b> on line <b>13</b><br > > /> > > > > However > > > > require_once("gibberator_data.php"); > > > > Works just fine. > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > >