Re: Undefined offset on Windows not on Apache?

I don't believe the disputed line of script is being executed because just before that line I include the following print statement, echo "array size: " . count($zip_forward) . " ID: $location_id<br>"; which does not get executed when my conditional fails. Right you are on the error reporting, I included error_reporting (E_ALL); in my test script and can reproduce same error on Apache. Chris "John W. Holmes" <holmes072000@charter.net> wrote in message news:3FCA2F4C.3090206@charter.net... > Chris Williams wrote: > > The first and last lines contain carriage returns. The second or middle line > > contains sample data. > > > > The script that reads and parses the data is: > > > > $countLines = fopen("data.txt", "r"); > > while (!feof($countLines)) > > { > > $newLine = fgets($countLines, 1024); > > echo "line length: " . strlen($newLine) . "<br>"; > > if(strlen($newLine) > 0) > > { > > $newLine = ereg_replace ("\"", "", $newLine); > > $zip_forward = explode(",",$newLine); > > $location_id = trim($zip_forward[0]); > > echo "array size: " . count($zip_forward) . " ID: > > $location_id<br>"; > > $zip_to = trim(substr($zip_forward[1], 0, 5)); > > } > > } > > fclose($countLines); > > > > What's odd here is that the last line, which has a length of 0, should never > > cause the if(strlen($newLine) > 0) to execute the lines of script contained > > within the if conditional. And in fact the lines DON'T get executed. > > However, on the Windows server I get the following error > > PHP Notice: Undefined offset: 1 in \debug.php on line 20. This points to my > > code that evaluates the second element of the array $zip_to = > > trim(substr($zip_forward[1], 0, 5)); > > > > If I never evaluate the $zip_forward[1] array element within the if > > conditional, why would PHP test the array $zip_forward for the proper number > > of elements? > > Okay, if you're getting that NOTICE then the line of code is executing. > So even though you think the strlen() line is failing, it's not. > > Anyhow, the whole issue here is just that your two servers have > different error_reporting() levels. One is set to show NOTICES while the > other is not. If you use @trim(...), you can suppress this warning. > > The code is running the same on both servers, though... > > -- > ---John Holmes... > > Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ > > php|architect: The Magazine for PHP Professionals – www.phparch.com