Re: new set of eyes?

From: Date: Sat, 06 Dec 2003 19:48:46 +0000
Subject: Re: new set of eyes?
References: 1 2 3  Groups: php.general php.general 
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Ok well I think I have it partially solved... <?php $table = "settings"; $db_vlans = array("hosts01","hosts02","hosts03","hosts04","hosts05","hosts06","hosts07","hosts08","hosts09","hosts10"); $vlans = array("VLAN-22","VLAN-27","VLAN-29","VLAN-56","VLAN-57","VLAN-151","VLAN-314","Empty-01","Empty-02","Empty-03"); $i = str_replace($vlans,$db_vlans,$_POST['dhcp_hosts']); $_SESSION['dhcp_table'] = $i; $sql = mysql_query("SELECT $i FROM $table WHERE $i = $i",$db)or die(mysql_error()); $result = array(); while($b = mysql_fetch_array($sql)) { $result[] = explode(" ",$b);
         	   print_r($result);
$num = count($result); print $num; for ($x = 0; $x < $num; $x++) { print "$result[$x]<br />\n"; } ?> On data in "one" field that looks like: host dhcp-01 { hardware ethernet 00:D0:B7:BD:D2:8D; fixed-address 155.97.1.190; } host dhcp-02 { hardware ethernet 00:02:B3:A2:B6:FD; fixed-address 155.97.1.191; } Is returning this: Array ( [0] => Array ( [0] => Array ) ) 1Array So it sees 1 array and inside are two indexes both containing a new array... now I need to know how to pull the contents out of the second arrays. Sorry, still trying to figure out arrays. Jas

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