RE: [PHP] Php shell scripting [SOLVED]
| From: | Jake McHenry | Date: | Thu, 11 Dec 2003 05:45:56 +0000 |
| Subject: | RE: [PHP] Php shell scripting [SOLVED] | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-172440@lists.php.net to get a copy of this message | ||
> -----Original Message-----
> From: Evan Nemerson [mailto:evan@coeus-group.com]
> Sent: Wednesday, December 10, 2003 9:32 PM
> To: Jake McHenry; php-general@lists.php.net
> Subject: Re: [PHP] Php shell scripting
>
>
> On Thursday 11 December 2003 12:31 am, Jake McHenry wrote:
> > Does anyone know how I can pass variables into a script
> being executed
> > from the command line?
> >
> > I have a script, named testscript. So far, I have been
> getting all my
> > variables from the system env command, not a big deal. But
> I want to
> > input a username into the script, like testscript jmchenry.
> >
> > In basic shell scripting, the value of any parameters would
> be $1, $2,
> > $3, etc.. within the script, but how can I do this with PHP? Is it
> > even possible?
>
> var_dump($argv);
>
> >
> > Thanks,
> >
> > Jake McHenry
> > Nittany Travel MIS Coordinator
> > http://www.nittanytravel.com
>
> --
> Evan Nemerson
> evan@coeus-group.com
> http://coeusgroup.com/en
>
> --
> "They that can give up essential liberty to obtain a little
> temporary safety
> deserve neither liberty nor safety."
>
> -Benjamin Franklin
>
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>
Thanks for the very quick responses! Here's what I got from your
responses:
var_dump($argv);
This returned NULL, so I tried:
print_r($_SERVER['argv']);
This returned exactly what I wanted.
Thanks,
Jake McHenry
Nittany Travel MIS Coordinator
http://www.nittanytravel.com