RE: [PHP] Re: passing arrays?

Thank you Al for the pointers. This has been very helpful! -m > -----Original Message----- > From: Al [mailto:php.newsgroups@allysays.com] > Sent: Thursday, December 11, 2003 10:28 PM > To: php-general@lists.php.net > Subject: [PHP] Re: passing arrays? > > > > $level = '$level_' . $_SESSION['user']['level']; > > //Where $_SESSION['user']['level'] can equal "1" or > > "2" > > > > $level_1 = array("PN", "GALUP", "VP", "PUBUP", > > "STATS", "MCI", > "CONLIST", > > "CP", "OAFS", "LO"); > > $level_2 = array("PN", "GALUP", "VP", "PUBUP", > > "MCI", "CONLIST", "CP", > > "OAFS", "LO"); > > I can see two problems with your code: > > 1) The syntax for assigning to $level is wrong. > Rather than: > $level = '$level_' . $_SESSION['user']['level']; > your code should read: > $level = ${'level_' . $_SESSION['user']['level']}; > For more information on this syntax, see: > http://us2.php.net/manual/en/language.variables.variable.php > > 2) You are assigning $level_1 or $level_2 (depending on the value of > $_SESSION['user']['level']) to $level *before* you have assigned > $level_1 or > $level_2 any values. There's no point making $level = $level_1 if $level_1 > hasn't been defined yet. > > Working code would be: > > $level_1 = array("PN", "GALUP", "VP", "PUBUP", > "STATS", "MCI", "CONLIST", > "CP", "OAFS", "LO"); > $level_2 = array("PN", "GALUP", "VP", "PUBUP", > "MCI", "CONLIST", "CP", > "OAFS", "LO"); > $level = ${'level_' . $_SESSION['user']['level']}; > > Hope it helps, > > Al > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >