Re: include files
| From: | Marek Kilimajer | Date: | Sat, 20 Dec 2003 06:27:04 +0000 |
| Subject: | Re: include files | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-173055@lists.php.net to get a copy of this message | ||
See function debug_backtrace(), it's available since 4.3.3
Todd wrote:
Hi,
Is it possible under PHP4 to get the name of the file that a function was
called from? To clarify, here's an example of what I'd like to do:
--- main.php ---
<?php
include('include.php');
function foo(){
$include_file=file_that_called_foo();
printf($include_file);
}
?>
--- include.php ---
<?php
foo();
?>
Does anyone know of a way to do this? I've tried several different things,
including to constant '__FILE__ ', but they all return the current file, I
am needing the included filename.