newbie mysql and php
| From: | tony | Date: | Sun, 28 Dec 2003 00:17:48 +0000 |
| Subject: | newbie mysql and php | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-173387@lists.php.net to get a copy of this message | ||
hello
I'm new with php just learning and i have just a problem with the following
code
$dbconnect = mysql_connect("localhost", "prog_tony","PASSWORD");
mysql_select_db("prog_dealer", $dbconnect);
$stop = 0;
$counter = 1;
while(!$stop){
$query = "SELECT name FROM category WHERE id = $counter";
$dbdo = mysql_query($query,$dbconnect);
while($row= mysql_fetch_array($dbdo)){
if($row[0]){
$counter++;
}else{
$stop=1;
}
$row[0] = "";
}
}
I'm getting an error with mysql_fetch_array() which is line 14 because I
didn't show the other lines since it is not relevant.
here is the error
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /home/prog/public_html/php/cateadded.php on line 14
Thank you