Re: Compare Array Elements

One approach: for ($i=0; $i < sizeof($xArray); $i++) { if ($xArray[$i] == $yArray[$i]) { new_yArray(); break; } } "Wknit" <wknit@yahoo.com> wrote in message news:20040103145032.69533.qmail@pb1.pair.com... > I am a novice, I am sure this is pretty simple... > > I have two arrays of integers, equal length. > The arrays elements consists of the integers 0 through 9. > The order of the numbers in the arrays should always be different. > > Example 1: Is ok > xArray: 2 9 6 0 1 3 4 5 8 7 > yArray: 3 7 1 9 0 8 6 2 4 5 > > Example 2: Is not ok - the element "7" is in the same position in both > arrays. > xArray: 2 9 6 0 7 3 4 5 8 1 > yArray: 3 5 1 9 7 8 6 2 4 0 > > I need a snippet that will compare the value of each element in each > position and call a function to create a new array if the compare evaluates > to true. I assume that a foreach is the way to go, but I can't seem to find > the right syntax for it. > > ------- > if foreach (xArray as $x) == (yArray as $y) { > new_yArray (); > } > ------ > > I know this isn't correct, but in idiot terms, it is what I want to do... a > test/compare. Of course the compare should stop and call the function the > moment it evaluates to true at any given position. > > Maybe I should be using a "for" loop? (again, not a clue) > > Thanks anyone!