Re: Re: How to do this? 6 lines of code...Parse error
| From: | Ryan A | Date: | Sun, 04 Jan 2004 00:56:54 +0000 |
| Subject: | Re: Re: How to do this? 6 lines of code...Parse error | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-173701@lists.php.net to get a copy of this message | ||
Hey,
OK, got it, thanks!
-Ryan
On 1/4/2004 1:00:04 AM, Aidan Lister (aidan@virtualexplorer.com.au) wrote:
> Firstly
> I'd rewrite your other script to store the data in an array.
>
> The benefits of doing so are simply demonstrated:
>
> <?php
> foreach ($products as $product)
> dosomethingto($product);
> ?>
>
> However, if you are unable to rewrite your script:
>
> The correct syntax is:
> <?php
> ${'product' . $i}
> ?>
>
> "Ryan A" <ryan@coinpass.com> wrote in message
> news:004001c3d242$2ff18de0$0000fea9@l2zcaxu7emppqh...
> > Hi,
> > am a bit confused as to how you do this...first let me explain the flow
of
> > input:
> > I will be getting $product1,$product2,$product3 etc from another
> script...I
> > dont know till what number....right now I am trying to catch the values
> till
> > 20 with a "for" loop.
> >
> > My problem is how do I attach the $i that I am using to the $product to
> > check if its set? Heres my code and below that you will see some of the
> > stuff I have tried:
> >
> >
> > for($i=1; $i<21; $i++)
> > { if(isset($product$i))
> > {echo "Product".$i." is set!<br>";}
> > else(!isset($product$i))
> > {echo "Product".$i." is NOT set!<br>";}}
> > exit;