Re: How to do this? 6 lines of code...Parse error
| From: | Geoff Caplan | Date: | Mon, 05 Jan 2004 11:23:46 +0000 |
| Subject: | Re: How to do this? 6 lines of code...Parse error | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-173737@lists.php.net to get a copy of this message | ||
Hi,
RA> for($i=1; $i<21; $i++)
RA> { if(isset($product$i))
RA> {echo "Product".$i." is set!<br>";}
RA> else(!isset($product$i))
RA> {echo "Product".$i." is NOT set!<br>";}}
RA> exit;
...
RA> all of the above give me a parse error.
Your problem is here:
else(!isset($product$i))
You can't put conditions after "else": it is used as the default
option if all other tests fail. You should be using "elseif" instead.
Your choices are:
else
{
echo "Product" .$i. " is NOT set!<br>";
}
or
elseif(!isset($product$i)
{
echo "Product" .$i. " is NOT set!<br>";
}
In this case, as it seems to be a boolean test, the first is superior,
I think. The second test adds nothing...
Geoff Caplan
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