Re: Dynamically Created Arrays

This should be what you need: if(!is_array($conf[$name])) $conf[$name] = array($val); else $conf[$name][] = $val; Cameron B. Prince wrote:

Hey guys, I'm making progress on my perl to PHP conversion project but I need some help... I have a configuration table in MySQL made up like this: CREATE TABLE config ( code mediumint(9) NOT NULL auto_increment, site varchar(32) NOT NULL default '', name varchar(64) NOT NULL default '', value varchar(128) NOT NULL default '', seq smallint(4) default NULL, PRIMARY KEY (code) ) TYPE=MyISAM; It has data like this: | 1 | site1 | homedir | /var/www/htdocs/site1 | NULL |

| 2  | site1 | groupname | Group1                | 1    |
| 3  | site1 | groupname | Group2                | 2    |

I use this query to get the configuration data: SELECT name, value FROM config WHERE site = '$site' ORDER BY name, seq What I want to create is an array of arrays like this: $conf[$name][] = $val; or array_push($conf[$name], $val); So I end up with something like: $conf[homedir][0] = /var/www/htdocs/site1 $conf[groupname][0] = Group1 $conf[groupname][1] = Group2 If I were still in Perl-land, I'd use a hash of arrays and push things into it, but I don't seem to have that option now and I keep getting "Use of undefined constant name" errors. Am I going about this in the right way? Any help would be greatly appreciated. Thanks, Cameron