Re: Javascript Mouseover Help

I would be very interested in a solution to this problem because I have a similar one. I stored tables on a page. examp: $table_1 = "<table><tr><td>".$name."</td></tr></table>"; $table_2 = "<table><tr><td>".$message."</td></tr></table>"; etc... and included the page and used the variables (echo $table_1;) The table displayed as it should, however the variables didn't have values( for $name, $message, etc..) I began testing for the problem by defining the string variable for the table on the same page as the php code examp: <?php $table_1 = "<table><tr><td>".$name."</td></tr></table>"; $table_2 = "<table><tr><td>".$message."</td></tr></table>"; $name = "blah blah"; if(blah blah){ echo $table_1;} else{ echo $table_2;} ?> Again, the tables printed fine, but the variables ($name, $message) had no values. Most recently, I put the whole dam table in each conditional option. if (blah blah){ echo "<table><tr><td>".$name."</td></tr></table>";} else{ echo "<table><tr><td>".$message."</td></tr></table>";} Voila, the variables have values. It would seem that if a solution was found for Jake's problem it would also solve, or provide a key for solving, this one.