Re: Passing by conditional IF statement...why?
| From: | Ligaya Turmelle | Date: | Tue, 23 Mar 2004 01:33:45 +0000 |
| Subject: | Re: Passing by conditional IF statement...why? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-181215@lists.php.net to get a copy of this message | ||
I think it is because the query ran successfully and returns an empty set.
So the pointer is still good.
Respectfully,
Ligaya Turmelle
"Ryan A" <ryan@coinpass.com> wrote in message
news:000301c4106e$f4ddf390$f081aa51@l2zcaxu7emppqh...
> Hi,
> I have this simple code in my php script:
>
> * * * * *
> $res = mysql_query("SELECT product_id, now()-1 FROM ".$tc."_prods where
> cno=$cno AND product_id='$product_id' LIMIT 1");
>
> if($res)
> {
> $r = mysql_fetch_row($res);
> $product_id2 = $r[0];
> $th_pres= $r[1];
> echo "debug echo";
> }else {echo "No results, sorry";}
> * * * * *
>
> its working great when the data actually exists but when there are no
> matches it still executes the "if($res)" part instead of
> displaying "No results, sorry".
> Why is that? or am I using the syntax wrong?
>
> Thanks,
> -Ryan