SOLVED:Re: trying to output a hyperlink

Thanks for all the help, I overlooked a simple mistake in html, I was so much concentrating on concatenating the $link that I forgot to include the link I got a private email that solved it for me -- www.phpexpert.org/truefaith.htm "True Faith is not just when you believe in God and yourself, it is when others begin to believe in you as well" - Damian John Paul Brown 2004 "Andy Ladouceur" <ladouceur@shaw.ca> wrote in message news:20040411060842.98531.qmail@pb1.pair.com... > When in doubt, view source. :) As John has already mentioned, you need > text between the two tags to actually display in the browser. You > probably would've seen your mistake a lot sooner if you viewed the page > source when you first tried it out. > > Also, you can save yourself some time using PHP's shorthand > concatenation operator. > > > <td><?php $link = '<a href="' ; > > $link = $link . $row[2] . '">' ; > > $link = $link . '</a>' ; > > echo $link ; ?></td> > > Turns into: > > <td><?php $link = '<a href="'; > $link .= $row[2] . '">'; > $link .= 'Click here</a>'; > echo $link; ?></td> > > Although, it could be shortened even more, to: > > <td><?php $link = "<a href=\"".$row[2]."\">Click > here</a>"; > echo $link;?></td> > > But I imagine you're doing it with more lines for legibilities' sake. > > Andy > > Damian Brown wrote: > > <td><?php $link = '<a href="' ; > > $link = $link . $row[2] . '">' ; > > $link = $link . '</a>' ; > > echo $link ; ?></td> > > is not working, I want to output $row[2] as a hyperlink > > as it is the refering URL, but the above is just showing blank in the > > output, with no link and no text in the output table > > -- > > www.phpexpert.org/truefaith.htm > > "True Faith is not just when you believe in God and yourself, it is when > > others begin to believe in you as well" - Damian John Paul Brown 2004