RE: [PHP] eval() question

>> OrangeHairedBoy wrote: >>> I would like to use eval() to evaluate another PHP file and store >>> the output of that file in a string. >> >> You could use output buffering to do this a bit more easily, I think: >> >> ob_start(); >> include('colors.php'); >> $colors = ob_get_contents(); >> ob_end_clean(); > > While that is an awesome idea, I don't think it will work for me. > > There's two reasons why. First, colors.php is actually stored in a > MySQL server. > > Second, before the PHP code inside colors.php I want to be able to > replace data inside that file. For example: > > $file = str_replace( "Green" , "Orange" , $file ); Ok, then a slight adjustment should work: $file = file_get_contents( "colors.php" ); $file = str_replace( "Green" , "Orange" , $file ); ob_start(); eval( $file ); $colors = ob_get_contents(); ob_end_clean(); I've never done that personally, but the documentation for eval() states: In PHP 4, eval() returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. And then: Tip: As with anything that outputs its result directly to the browser, you can use the output-control functions to capture the output of this function, and save it in a string (for example). HTH...