Re: variable-length arguments passed by reference... how?
| From: | Curt Zirzow | Date: | Thu, 29 Apr 2004 22:44:32 +0000 |
| Subject: | Re: variable-length arguments passed by reference... how? | ||
| References: | 1 2 3 4 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-184981@lists.php.net to get a copy of this message | ||
* Thus wrote Tom Rogers (trogers@kwikin.com):
> Hi,
>
> Friday, April 30, 2004, 3:51:19 AM, you wrote:
>
>
> JB> I know I'm probably paranoid, but eval() always bugs me. I think for
> JB> what you want to do you can use call_user_func_array()
>
> JB> $args = func_get_args();
> JB> call_user_func_array('function_to_call', $args);
>
> JB>
> JB> http://www.php.net/manual/en/function.call-user-func-array.php
>
> The only time eval can be a problem is if you use it on client
> supplied data otherwise it is no worse than any other function.
It is *very* expensive to use eval, expecially when this has been
said:
If eval() is the answer, you're almost certainly asking the
wrong question. -- Rasmus Lerdorf, BDFL of PHP
Here are a couple alternatives:
function argbyref(&$args) {
$args['arg'] = 'changed';
}
$args['arg'] = 'not changed';
argbyref($args);
function argwitharray($args) {
$args['arg'] = 'changed';
}
$arg = 'not changed';
argwitharray(array('arg' => &$arg));
Curt
--
"I used to think I was indecisive, but now I'm not so sure."