Re: Print a variable's name

Thanks Ryan, but what I want is to be able to pass any variable to a procedure and have the variable name and value printed by the procedure. Can this be done? I'm trying to extend my library of debugging functions/procedures by having a procedure which can be used to "inspect" a variable whenever I call it. Thanks Ahbaid Ryan A wrote:

Just escape it... eg: $ryan = "something"; echo "\$ryan =".$ryan; that would print: $ryan = something HTH. Cheers, -Ryan On 5/5/2004 5:02:25 PM, ahbaid@att.net wrote:

I'd like to print a variable's name in a procedure along with it's

value....

Is there a way to do this? for example: --------------------------------------------------------------------------

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function showvar($somevar) { echo "Now showing: ". <....... code to show var name .....> ."\n"; echo "Value: ".$somevar; } $s1 = "Hello World"; showvar($s1); --------------------------------------------------------------------------

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would produce: --------------------------------------------------------------------------

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Now showing: $s1 Value: Hello World --------------------------------------------------------------------------

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many thanks in advance... Ahbaid -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php