Re: Include from another URL?

You could always use this : $text = ""; $fd=fopen($url,"r"); while ($line=fgets($fd,1000)) { $text.=$line; } fclose ($fd); echo $text; -- -- Kim Steinhaug ---------------------------------------------------------------------- There are 10 types of people when it comes to binary numbers: those who understand them, and those who don't. ---------------------------------------------------------------------- www.steinhaug.com - www.easywebshop.no - www.webkitpro.com ---------------------------------------------------------------------- "Nik" <nkarasev@usa.com> wrote in message news:20040506195845.90889.qmail@pb1.pair.com... > Hi there, > I'm new to these groups so forgive me if I'm asking at the wrong place (tell > me where then :) > > Ok, > I'm not PHP guru but I need to create a simple script that would do this: > > Include a content from another URL into the current output. I have done > something like > this: > > ------ code start > <?php > include 'http://myotherurl.com:8080'; > ?> > ------ code end > > and it seems to work with one exception: it produces a warning message > saying something like > "Warning: main(): stream does not support seeking in .../web-root/index.php > on line 9" > where line #9 is: include 'http://myotherurl.com:8080'; from above code. > It then shows a message from 'http://myotherurl.com:8080' > > Thanks!!! > Nik