Re: $myobject->$$varname doens't work ??

"Greg" <news.php.net@gb404.com> wrote in message news:20040509071800.74440.qmail@pb1.pair.com... > Hello, > > I was just trying this but it doesn't work : > <?php > > class a { > public $foo = "hello world"; > } > > $obj = new a(); > $varname = "foo"; > echo $obj->$$varname; > $$varname is turned into $foo, what is the value of $foo? If you're trying to access "public $foo" then Richard was entirely correct (sorry richard!), just do it like so: $a->foo If, like in the below example, $foo is the name of a variable that you want to access, then try ${$foo}, everynow and then there's a problem to that effect Good luck, welcome to oop :) > $bar = "this is working"; > $varname = "bar"; > echo $$varname; // display "this is working" as expected > ?> > > Is it a bug or is it normal ? > I didn't find anything about it in documentation (php4 / php5). > > Greg