Re: Dropdown menu
| From: | William Stokes | Date: | Tue, 11 May 2004 11:07:09 +0000 |
| Subject: | Re: Dropdown menu | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-185895@lists.php.net to get a copy of this message | ||
Thanks! I found the answer from:
http://codewalkers.com/tutorials.php?show=12
"Daniel Clark" <dclark@nwlink.com> kirjoitti viestissä
news:20040511105226.657A96F153@smtp1.pacifier.net...
> Hi Bill.
>
> Put something like:
> <FORM ACTION="read_form.php" METHOD="post">
>
> ##your form selections here##
>
> </FORM>
>
> Then on your read_form.php page:
>
> $what_they_selected = $_POST['name1']
>
>
> >>A question about forms and PHP. I have a dropdown list which gets the
lines
> >>in the list from DB. Like this(col1 is used only for sorting the data):
> >>
> >>echo "<td>choose one:</td><td><SELECT
> >>NAME=\"name1\">";
> >>$sql="SELECT col1, col2 FROM table_04 ORDER BY col1";
> >>$result=mysql_query($sql);
> >>$num = mysql_num_rows($result);
> >>$counter = 1;
> >>while ($num >= $counter) {
> >>$row = mysql_fetch_array($result);
> >>$col2 = $row["col2"];
> >>echo "<option value=\"name\">$col2</option>";
> >>$counter++;
> >>}
> >>
> >>This obviously leaves the value of $col2 to what ever is in the last row
in
> >>database. How do I set the script to change the value when user selects
> >>another name from the list? I need to do more stuff based on the users
> >>selection. How do I get the selection from the list to a variable? I
haven't
> >>really done forms and PHP before ;-)
> >>
> >>Thanks
> >>Bill