php as CGI and $_POST

Hi, all -- I am working up a CGI script to take advantage of Apache's suEXEC so that the web server can manipulate files as the site owner. I have already managed a simple $f = fopen("/path/to/docroot/testfile",'w') ; fwrite($f,"hi!\n") ; fclose($f) ; and know that it works as intended, but now I seem completely unable to get any $_POST (or even $_GET) data into the script. I suspect, from reading the manual and noting the warnings, that any GET data will be ignored, and that's fine, but I know that I can provide that without even messing about with a form that I might somehow be screwing up, so I thought I'd try it... My code is as simple as #!/usr/local/bin/php <?php print "Content-type: text/html\n\n" ; print "_POST IS ." ; print_r($_POST) ; print ".<br>\n" ; print "_GET IS ." ; print_r($_GET) ; print ".<br>\n" ; print "Enter your password:<br>\n" ; print "<form method='post'>\n" ; print "<input type='password' name='pass'>\n" ; print "<br>\n<input type='submit' value='ENTER'>\n" ; print "</form>\n" ; exit ; ?> but I only get _POST IS .Array ( ) . _GET IS .Array ( ) . Enter your password: ____________________ ENTER even after submitting. Switching to <form method='get'> doesn't help anything. So how on earth does one get data into a CGI PHP script? TIA & HAND :-D -- David T-G davidtg@justpickone.org http://justpickone.org/davidtg/ Shpx gur Pbzzhavpngvbaf Qrprapl Npg!