Re: Problems with variable handling !

From: Date: Tue, 08 Jun 2004 11:13:35 +0000
Subject: Re: Problems with variable handling !
Groups: php.general 
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On Tuesday 08 June 2004 18:50, php-general wrote: > Only pressing the "Display concatenated strings"-button should > output the concatenated string, but this does not work, and I do not > understand why. $var3 is not defined. -- $var3 is defined as $var3 = "$var1$var2"; in the body of the if ($button1) statement !?

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