RE: [PHP] Passing args to a PHP script from the command line

Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 15:11: >> Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 14:27: >> >>>> Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 12:58: >>>> >>>>> Hi All, >>>>> >>>>> Can anyone tell me how to pass arguments to a PHP script from the >>>>> command line? I know I need to use the -args option but how >>>>> exactly, I have tried the following... >>>>> >>>>> /usr/bin/php myscript.php -args key=value >>>> >>>> You don't have to call the -args argument. just run the script >>>> from command line like this: >>>> >>>> php myscript.php value >>>> >>>> Where value is the argument you want to use in the script. >>>> These arguments are stored in an arrray ($argv). >>>> >>>> Do a print_r($argv) and you can see the content. >>> >>> OK, but if no param name is passed in, I assume that the order they >>> are passed in as must be correct or the script will not know what >>> values belong to which parameters? This seems a little odd, I assume >>> that $argv only exists when accessed from the command line? My >>> script needs to be excuted from both command line and from web >>> browsers. >>> >> >> How do you mean the order must be correct. Use some code like this >> to give it an index value. for ($counter=0; $counter < $argc; >> $counter++) { list($key, $value) = each($argv); >> echo ("key ". $key . "has value : " . $value . "\n"); >> } > > Your example was... > > php myscript.php value > > That is just a value, no parameter name as with a query string, take > this example... > > php myscript.php a b > > Let's say that this was requested from a browser like > myscript.php?1=a&2=b > > PHP uses 1 & 2 to refer to the values, but the values would get mixed > up if I was to use... > > $argv[0] & $argv[1] > > and the order of a and b were different when the script was called. > Does that make sense? I find it odd that I need to write more code to > 1) check $_GET and 2) check $argv, also simple error checking will > fail for command line stuff when checking that all the required > params are present. > > ic now i understand what you mean :) Why not just pass the arguments on commandline like this: php myscript.php 1=a 2=b and then just split on '=' to get key & value. >>> From what i understand the argv & argc are only avaliable when the >> script is run from commandline. Just do a check on this and if not >> there get some $_POST or $_GET variables. >> >>>> >>>>> >>>>> but this does not work, the script executes but key is not >>>>> available as $_GET["key"] in my script. Any pointers will be much >>>>> appreciated. >>>>> >>>>> TIA >>>>> >>>>> Phil. >>>>> >>>>> --- >>>>> Phil Ewington - Technical Director >>>>> >>>>> 43 Plc - Ashdale House >>>>> 35 Broad Street, Wokingham >>>>> Berkshire RG40 1AU >>>>> >>>>> T: +44 (0)1189 789 500 >>>>> F: +44 (0)1189 784 994 >>>>> E: mailto:phil.ewington@43plc.com >>>>> W: www.soyouthink.com >>>>> >>>>> --- >>>>> Outgoing mail is certified Virus Free. >>>>> Checked by AVG anti-virus system (http://www.grisoft.com). >>>>> Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 >>>> >>>> --- >>>> Incoming mail is certified Virus Free. >>>> Checked by AVG anti-virus system (http://www.grisoft.com). >>>> Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 >>>> >>> --- >>> Outgoing mail is certified Virus Free. >>> Checked by AVG anti-virus system (http://www.grisoft.com). >>> Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 >> >> --- >> Incoming mail is certified Virus Free. >> Checked by AVG anti-virus system (http://www.grisoft.com). >> Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 >> > --- > Outgoing mail is certified Virus Free. > Checked by AVG anti-virus system (http://www.grisoft.com). > Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004