Re: issue with inheriting private property from abstract class
| From: | Chris | Date: | Wed, 23 Jun 2004 22:35:14 +0000 |
| Subject: | Re: issue with inheriting private property from abstract class | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-188920@lists.php.net to get a copy of this message | ||
ok, i understand now that private members are NOT inherited. i guess it was just throwing me off that var_dump()/print_r() display the parents private member, even tho its not really a member of the subclass.
thanks
Marek Kilimajer wrote:
Chris wrote --- napísal::if anyone can, would you please explain why the below code does what it does? I would expect $this->test in TestInstance to refer to the inherited $test from Test. Using php5RC3. Thanks. <?php abstract class Test {The variable is private for Test, so TestInstance does not have access to it. By assigning 0 to $this->test in the constructor of TestInstance, you create a new property of TestInstance that is public (the default). var_dump() shows it clearly: object(TestInstance)#1 (2) { ["test:private"]=> NULL <---- belongs to Testprivate $test; abstract public function addToTest($i);} class TestInstance extends Test {public function __construct() { $this->test = 0; }public function addToTest($i) { $this->test += $i; }} $t = new TestInstance(); $t->addToTest(3); var_dump($t); // test var SHOULD be private echo "private test (shouldn't be able to access it directly, but i can): ".$t->test."\n\n"; /* output ------------------------------- object(TestInstance)#1 (2) { ["test:private"]=> NULL ["test"]=> int(3) } private test (shouldn't be able to access it directly, but i can): 3 */ ?>["test"]=> int(3) <---- belongs to TestInstance}