Re: Re: test if $int is integer

Yeah, 4 will pass the is_int() test, '4' won't. I prefere just to use if(ctype_digit($foo)){ ... } On Tue, 29 Jun 2004 15:12:22 -0700 (PDT), Matthew Sims <matt@killermookie.org> wrote: > I recently purchased George Schlossnagle's Advanced PHP Programming and on > page 85 in the Error Handling chapter, he made a reference about the > is_int function. > > In the above function example he had: > if (!preg_match('/^\d+$/',$n) || $n < 0) {.... > > In which he mentions: > It might be strange to choose to evaluate whether $n is an integer by > using a regular expression instead of the is_int function. The is_int > function, however, does not do what you want. It only evaluates whether $n > has been typed as a string or as an integer, not whether the value of $n > is an integer. > > Can anyone comment on this? > > --Matthew Sims > --<http://killermookie.org>