Re: php 4.3.7/5.0

I think I'll just have to typecast everything, that should always work then. On Tue, 13 Jul 2004 15:47:40 -0400, Adam Bregenzer <adam@bregenzer.net> wrote: > On Tue, 2004-07-13 at 15:35, Josh Close wrote: > > The problem is, if 0 gets changed to "0" somewhere throughout. That's > > why I've always used if($var) because it's usually not cared what the > > type is, but it seems to now. > > You can typecast values as well, this may be a good way to achieve what > you are looking for: > if ((int)$var != 0) { > // Do Something > } > > Also, if you are going to use this variable as an integer later you can > do the following to explicitly convert $var into an integer: > $var = (int)$var; > > That should convert "0" into the integer value 0. Also, note the > following: > > var_dump(0 == "0"); //bool(true) > var_dump(0 === "0"); //bool(false) > > -- > Adam Bregenzer > adam@bregenzer.net > http://adam.bregenzer.net/ > > -- -Josh