You don't have to declare an array size in PHP. First you can do this:
$arr = array();
then
$arr[1] = 50;
$arr[2] = true;
$arr[3] = "some value";
or you can loop through
foreach( $i = 0; $i < 50 ; $i++ )
$arr[$i] = false;
I believe you can assign the checkbox names in HTML as grid[] and in php the array value will be filled in for you.
Jon
Henri Marc wrote:
Hello,
I'm just starting with PHP and I have a problem. This is certainly very easy for you but for me, it's tough.
I want to make a lottery site (just as an exercise), so I made a page with 6 grids of 50 numbers each (check boxes).
Now, I want to know which numbers have been checked by the player.
I have a :
"input name="Grid1" type="checkbox"
for the first grid. Grid2 for the grid #2...
I was thinking to get the numbers chosen by the player with $_POST['Grid1[]']
Grid1 being a table but it doesn't work. I thought I wouldn't have to declare an array. I have 50 numbers for each grid, I don't want to have to type array followed by the 50 numbers. There is not a way to do something like array(1...50).
What is the solution?
Thank you very much (in advance) for your help.
Dave
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