RE: [PHP] Array help

From: Date: Fri, 23 Jul 2004 22:23:56 +0000
Subject: RE: [PHP] Array help
Groups: php.general 
Request: Send a blank email to php-general+get-191701@lists.php.net to get a copy of this message
Robb Kerr wrote: > On Fri, 23 Jul 2004 14:21:42 -0700 (PDT), Matthew Sims wrote: > >> imgBkgrnd = array("1"=> "bkgrnd-default.gif", "2" => >> "bkgrnd-positive.gif", "3" => "bkgrnd-negative.gif"); > > You got it... > > imgBkgrnd = array("1"=> "bkgrnd-default.gif", "2" => > "bkgrnd-positive.gif", "3" => "bkgrnd-negative.gif"); > imgNeeded = > table['field']; imgName = ??? > > Now, how do I get the image name associated with the key number > obtained from my table out of the array and into the variable so that > I can use it later in the HTML? > > Thanx, Robb > -- > Robb Kerr > Digital IGUANA $imgBkgrnd[i] where 'i' is the number returned from your DB. HTH. Pablo

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