Re: Nested If...Else...
| From: | Robb Kerr | Date: | Sat, 24 Jul 2004 16:16:37 +0000 |
| Subject: | Re: Nested If...Else... | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-191744@lists.php.net to get a copy of this message | ||
On Sat, 24 Jul 2004 12:09:41 -0400, Scot L. Harris wrote:
> On Sat, 2004-07-24 at 12:05, Robb Kerr wrote:
>> What's wrong with this syntax. I just can't see my mistake.
>>
>> if ($vBkgrndImage == "AnswerPage") {
>> if ($vAnswerID_RS_PageContent != $row_RS_PageContent['CorrectAnswer']) {
>> $vBkgrndImage = "Bkgrnd-Body-Incorrect.jpg";
>> } else {
>> $vBkgrndImage = "Bkgrnd-Body-Correct.jpg";
>> }
>> }
>>
>> Thanx
>
> Single quotes around CorrectAnswer?
>
> What is the error you are getting?
>
> Guessing that if it passes the syntax checks I expect your problem is it
> is always evaluating to one of the options and not the other.
You've got it. Syntax passes checking - always returns..
$vBkgrndImage = "Bkgrnd-Body-Correct.jpg"
Single quotes around 'CorectAnswer' is because that entry is in the style
of table_recordset['field']. How else should this be coded?
Thanx
--
Robb Kerr
Digital IGUANA