Re: list($bar['CompanyCode'], $CompanyDB) = mysql_fetch_row($sth) fails.
| From: | Jason Davidson | Date: | Thu, 29 Jul 2004 05:07:18 +0000 |
| Subject: | Re: list($bar['CompanyCode'], $CompanyDB) = mysql_fetch_row($sth) fails. | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-192154@lists.php.net to get a copy of this message | ||
check the manual for list. It mentions using only numerical array
indices for list. There is a warning on it even i beleive.
Jason
On Wed, 28 Jul 2004 20:47:37 -0700, Daevid Vincent <daevid@daevid.com> wrote:
> Linux. PHP5.
>
> Why does this fail when using an array element, but using a variable will
> work? Why should PHP care what the variable is I'm trying to store into?
>
> list($bar['CompanyCode'], $CompanyDB) = mysql_fetch_row($sth);
>
> But this works:
>
> list($foo, $CompanyDB) = SQL_ROW($sth);
>
> And of course I'd have the extra...
> $foo = $bar['CompanyCode'];
>
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