Re: Variable functions within an object

* Thus wrote Julio Sergio Santana: > > Curt Zirzow wrote: > > > $this->{$this->fname}(); > > > > or (what it actually is doing.. ) > > > > $func = $this->fname; > > $this->$func(); > > > >Curt > > The point here is that the named function is outside the object. That > is, $this->foo() doesn't exist, so $this->{$this->fname}(), does not > work either. > But if you look at your suggested construct, I wonder why > $this->{$this->fname}() is sintactically correct while > {$this->fname}() is not (since we just striped out the prefix '$this->' > which means that the function is inside the object). Sorry, i did misread what actual function you were trying to access, the problem is that {} isn't really the thing that expands the variable its the special cases: ->{} ${} {} by itself simply defines a code block. > ... > > Clearly, $this->fname() means "call the object's method 'fname'", > but > {$this->fname}(), would mean "call the function whose name is > '$this->fname'". > I think, for the sake of orthogonallity, this feature should be added to > the language. One way to solve this without adding a feature like that would be: ${$this->fname} = $this->fname; ${$this->fname}(); or for the oneline purists :) ${ ${$this->fname} = $this->fname }(); wow.. ${} is more powerful than i had originally though. Curt -- First, let me assure you that this is not one of those shady pyramid schemes you've been hearing about. No, sir. Our model is the trapezoid!