Re: MySQL error

From: Date: Tue, 10 Oct 2000 01:13:08 +0000
Subject: Re: MySQL error
References: 1  Groups: php.general 
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On Tue, 10 Oct 2000, Brian Rue wrote: > Hi, > > I'm getting the following error: > Warning: Supplied argument is not a valid MySQL result resource ..... > > Here's the code: > $query="SELECT * FROM games WHERE > genre=$gameone_genre&number=$gameone_number"; > $info=mysql_query($query,$db); > $row=mysql_fetch_row($info); > > The last line is the one causing the error. What am I doing wrong? > Not reading the FAQ? Use mysql_error() after your database call to see what error is being returned. At a guess I'd say that the lack of spcaes in yuor SQL query could be a problem; also if either of the fields you are trying to insert are type char you need to delimit the value being inserted with single quotes. -- David Robley | WEBMASTER & Mail List Admin RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/ AusEinet | http://auseinet.flinders.edu.au/ Flinders University, ADELAIDE, SOUTH AUSTRALIA

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