Re: PHP, over javascript code simple \n

From: Date: Fri, 20 Aug 2004 09:49:10 +0000
Subject: Re: PHP, over javascript code simple \n
References: 1  Groups: php.general 
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<?php print(" if (document.rpcjs_louie.ColCustName.value == \"\") { walangfield += \"Missing: Firstname\n\"; } "); ?>
try simply escaping the "\" before the "n" with an additional "\" or in other words: use "\\n" instead of "\n". PHP will interpret "\\" as an "\".

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