Re: WAHT is my error???

On Fri, 20 Aug 2004 19:34:51 +0100, Andre <andre_caridade@sapo.pt> wrote: > > Inside of one ARRAY can I make one WHILE > > function tabelas($tabela_tipo){ > $sql = mysql_query("SELECT * FROM ".$tabela_tipo."_credito ORDER BY > ".$tabela_tipo."_ordenar"); > $return = "<select name=\"tabelas\" > class=\"textblack\">\n"; > $tabela_array = array("". No, you can't do such a thing. First of all, array() is a language construct and creates an array from values passed into it. Second, you're using period (.) here...what exactly are you trying to do? Perhaps you should try: $tablea_array = array(); > while($registo = mysql_fetch_array($sql)){ > array ("".$registo[0]."", *WHY* are you concatenating a value to two empty strings? This effectively changes the type of the variable to a string, but since it's coming from the DB it's already a string. And besides which, it very rarely matters to PHP whether something is a string or a number, it will convert between them automatically. > "".$registo[0]."&nbsp;".$registo[0].""); Maybe you mean to do: $tablea_array[] = array ($registo[0], $registo[0].'&nbsp;'.$registo[0]); > }."" And remove the ."" here. > foreach($tabela_array as $subarray) { > list($num, $text) = $subarray; > $return .= "<option value=\"$num\" > selected>$text</option>\n"; > } > $return .= "</select>\n"; > return $return; > } > You really need to go back and run through some PHP tutorials, it seems you don't really understand the language. -- DB_DataObject_FormBuilder - The database at your fingertips http://pear.php.net/package/DB_DataObject_FormBuilder paperCrane --Justin Patrin--