Re: Re: [PHP5]__get, __set and isset()

Yes.... but not :-). With you use these magic functions, when you write $o->a = 'foo', you create a property in the object. Not ? Even if it is stored in an array member, __set() create a property and __get() retrieve its value. Doc says :

The $name parameter used is the name of the variable that should be set or retrieved. The __set() method's $value parameter specifies the value that the object should set set the $name.

Conclusion : class OO { private $elem = array(); public function __get ($prop) {

      if (isset($this->elem[$prop])) {
         return $this->elem[$prop];

} else {

      return NULL;

} public function __set ($prop, $val) {

      $this->elem[$prop] = $val;

} } $o = new OO(); echo isset($o->a) ? "yes\n" : "no\n"; # Must return false and return false effectively, cool $o->a = 'foo'; echo isset($o->a) ? "yes\n" : "no\n"; # Must return false and return false effectively, NOT COOL Fred. Catalin Trifu wrote:

        Hi,

    Is this really a bug. I think not.
    There is no variable $o->a or $a->b in the class OO

there is only the variable $elem and $a and $b is a member of that array

    So ...
    The fact that PHP5 provides __set and __get magic

functions does not mean that the actual variables exist with that particular name in the class ?

    Perhaps it would be nice to have a __isset magic function ?

Cheers Catalin

<?php class OO { private $elem = array("a" => 1); public function __get ($prop) { if (isset($this->elem[$prop])) { return $this->elem[$prop]; } else { return NULL; } } public function __set ($prop, $val) { $this->elem[$prop] = $val; } } $o = new OO(); echo isset($o->a) ? "yes\n" : "no\n"; echo isset($o->b) ? "yes\n" : "no\n"; echo is_null($o->a) ? "yes\n" : "no\n"; echo is_null($o->b) ? "yes\n" : "no\n"; ?> I expected something like this: yes no no yes But got this: no no no yes It looks like isset() can't handle object properties correctly. I'll post the bug on php.net. -- Daniel Schierbeck

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