Re: ERROR IN THIS CODE

I resolve the problem. Thank you for all. ----- Original Message ----- From: "Jorge" <jorvgl@telefonica.net> To: <php-general@lists.php.net> Sent: Sunday, September 05, 2004 6:23 PM Subject: [PHP] ERROR IN THIS CODE the problem is that when i do a echo shows me: "SELECT * FROM oposicions WHERE id = ''" ----- Original Message ----- From: "raditha dissanayake" <jabber@raditha.com> To: "Jorge" <jorvgl@telefonica.net> Cc: <php-general@lists.php.net> Sent: Sunday, September 05, 2004 6:01 PM Subject: Re: Fw: [PHP] ERROR IN THIS CODE

Is this part of a guessing game? do you want us to guess the error message you are seeing? Jorge wrote:

include('include/conexion.php');

       include('include/conf.php');

                                       $sql = "SELECT * FROM oposicions WHERE id = '$id'";----------------> I think that the problem is here.

                                           $result = mysql_query($sql, $link);

                                           while( ($row=mysql_fetch_object($result)) ) {
                                           $nome = $row->nome;

In my database exist the table oposicions with a field called id.My php version es 4.3.38 and of mysql is 3.23.58 thank you in advance

-- Raditha Dissanayake. ------------------------------------------------------------------------

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