RE: [PHP] OK ... WHY does this work ?????

Read over some of the examples at: http://us4.php.net/types.array If you don't set a key, PHP starts with '0' and increments as you add more elements to the array. If you have "NOTICEs" turned on, I believe you'll get a notice saying that $arrlevels[99] doesn't exist. It's not a fatal error, so PHP just passes over it and doesn't say anything unless you tell it to. # One dimensional array $arrlevels = array(1,2,3); # Three dimensional array. $lvl_guest is a key and 'levelname' is a key $arrlevels[$lvl_guest]['levelname']; -TG > On Tue, 14 Sep 2004 22:32:54 +0200, -{ Rene Brehmer }- > <metalbunny@metalbunny.net> wrote: > > Unless I misunderstand how PHP make unspecified arrays (and > I probably do > > since this works), when you have an array of 3 elements on the first > > dimenstion like I do, and then ask for > $arrlevels[$lvl_guest]['levelname'], > > which in this case actually means it asks for > $arrlevels[99]['levelname'] > > .... how come it pick the correct element, and not error > out that element > > 99 don't exist ?? > > > > My only conclusion (based on the fact that this actually > works) is that PHP > > makes the key the same as the value if the key isn't > specified. But is this > > actually correct ???? Or is there something "going on" that > I don't know > > about ???