RE: [PHP] fopen problem, 5 line script
| From: | Vail, Warren | Date: | Wed, 15 Sep 2004 17:01:02 +0000 |
| Subject: | RE: [PHP] fopen problem, 5 line script | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-196756@lists.php.net to get a copy of this message | ||
I thought filesize required the file name, and not the fileptr???
Warren Vail
-----Original Message-----
From: Curt Zirzow [mailto:php-general@zirzow.dyndns.org]
Sent: Wednesday, September 15, 2004 10:17 AM
To: php php
Subject: Re: [PHP] fopen problem, 5 line script
* Thus wrote Mag:
> Hi,
> Can someone tell me what I am doing wrong here please?
>
> <?php
> $fileptr =
>
> fopen("http://www.google.com/index.html","r");
>
> $contents = fread($fileptr, filesize($fileptr));
>...
>
> This is the error I get:
> Warning: filesize(): Stat failed for Resource id #1
> (errno=2 - No such file or directory) in
> /home/quickxxx/public_html/tpg/ check- remote.php on line 4
>
> Warning: fread(): Length parameter must be greater
> than 0. in /
> home/quickxxx/public_html/tpg/check-remote.php on line
filesize() relies on the fact that the file you opened has support for
stat(). the http wrapper does not have such a thing.
see:
http://php.net/filesize
http://php.net/wrappers.http
Curt
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