Re: opening table 2 inside table1
| From: | John Taylor-Johnston | Date: | Sat, 25 Sep 2004 02:13:18 +0000 |
| Subject: | Re: opening table 2 inside table1 | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-197804@lists.php.net to get a copy of this message | ||
Curt,
Thanks.
> > #mysql_select_db($db2,$myconnection2); #not necessary
>
> Why isn't this necessary? if you have just opened a connection you
> must select a database. Besides the fact that the second connection
> isn't necessary.
>
From what I have experimented with, if I declare $db.$table in my sql, it is no longer necessary:
$sql2 = 'select participant,biography,district from '.$db.'.'.$table2.'
where district=$mydata1->district';
> > while ($mydata1 = mysql_fetch_object($news))
> > {
> > echo "$mydata1->district<br />$mydata1->meeting<br
> > />$mydata1->time<br />\n";
> >
> > $sql2 = 'select participant,biography,district from
> > '.$db.'.'.$table2.' where district=$mydata1->district';
>
My error was in the single quotes.
> If you need the stylesheet to go along with this see
> php-css@lists.php.net :)
Thanks. I Will look athtat.
John
> HTH.
Thanks, yes.