Re: Function declaration failing on return value
| From: | Whil Hentzen | Date: | Mon, 04 Oct 2004 22:19:23 +0000 |
| Subject: | Re: Function declaration failing on return value | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-198625@lists.php.net to get a copy of this message | ||
On Monday 04 October 2004 16:43, Matthew Sims wrote:
> > Don't get too excited; this is an awfully lame newbie question.
>
> Too late, I'm already excited.
Sorry 'bout that.
> > <?php
> > function square($num)
> > {
> > return $num * $num;
> > }
> > echo square(4); // outputs '16'.
> > ?>
> >
> > <br>
> > </body>
> > </html>
> >
> function square($num) {
>
> $result = $num * $num;
> return $result;
>
> }
Well, under the category of "That's weird", I changed the function to:
<?php
function square($nn)
{
$res = $nn * $nn;
return $res;
}
and it works now. Mebbe there's goofy hidden chars in the online help?
Back to the drawing board.
Thanks!
--
Whil
Moving to Linux: Freedom, Choice, Security, Opportunity
http://www.hentzenwerke.com