RE: [PHP] Is there any way of knowing User Currently Logged On?

From: Date: Tue, 12 Oct 2004 04:53:38 +0000
Subject: RE: [PHP] Is there any way of knowing User Currently Logged On?
Groups: php.general 
Request: Send a blank email to php-general+get-199247@lists.php.net to get a copy of this message
Hi Vail, My Worry is that If a remote OS is not Windows, then this would throw out garbage, Where as this Perl Script would work well at a Windows Side ,Bcoz I am using the 'Win32' Module ,is there any other module such that ..... We cannot even predict ( or I believe there is no exact way ) what the remote OS could be :( Nikhil. -----Original Message----- From: Vail, Warren [mailto:Warren.Vail@schwab.com] Sent: Monday, October 11, 2004 11:33 PM To: 'Mulley, Nikhil'; php-general@lists.php.net Subject: RE: [PHP] Is there any way of knowing User Currently Logged On? If you code in php something like the following, you just might be able to use the perl script; $ok = exec("path/to/Perl myperscriptname.pl server", $result); // you may have to straighten out syntax Foreach($result as $line) { echo $line; // or you could process the results } Hope this helps, Warren Vail -----Original Message----- From: Mulley, Nikhil [mailto:mnikhil@corp.untd.com] Sent: Monday, October 11, 2004 9:52 AM To: php-general@lists.php.net Subject: [PHP] Is there any way of knowing User Currently Logged On? Hi Guys, Is there any way of finding the current user logged on the remote system I have a perl script which gets the user name who is currently logged on a remote Windows Machine #LoggedOnUsers(server, userRef).pl use Win32::NetAdmin; use strict; use vars qw($server @users_list); if(@ARGV>0){ $server=$ARGV[0]; } else{ print "\n\nEnter a valid Hostname or IP Address : "; chomp($server=<STDIN>); } Win32::NetAdmin::LoggedOnUsers($server,\@users_list); foreach(@users_list) { print "\n$server -- $_"; } This one gets the users logged in on a remote Windows machine , Is there a similar way of finding / doing the same regardless of an OS, Can it be done through a Web Browser ???? Any Clues ?? --Nikhil.

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