Re: filtering out array values

Jason Wong wrote:

On Tuesday 02 November 2004 13:32, Merlin wrote:

I am retrieving some values out of the db and would only like to show those available inside a drop down field. Now I do have 2 arrays which fill the drop down field and one array with the values which should only show up. Example: $objects_available = array(3,5,7); $ob_options = array( 'all available', 'accomodations', 'internet access', 'tour operators', 'restaurants' , 'pubs', 'clubs', 'museums', 'secret spots', 'hotels at the airport'); $ob_values = array( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9); Has anybody an idea how to filter just the ones out which are inside the objects available array? I am sure this is possible without any if statements, but just cant come up with a clear programming solution.

Assuming that '0' corresponds to 'all available', '1' to 'accomodations' etc, then: foreach ($objects_available as $key) {

    echo $ob_options[$key];

}

This did not work. Here is how I solved it: $key = array_search($ob_values[$h], $object); if ($key !== false) printf ("<option value = \"%s\"%s>%s</option>\n", $ob_values[$h],$isselected,$ob_options[$h]); Merlin