RE: [PHP] blank function parameters

Hi, when declaring function function example($var1, $var2, $var3, $var4="anything") { } Now calling Example("one","two","three"); will not throw an error, but pass 'anything' as the value of $var4 by default if you override the value pass all the argumets. Zareef ahmed -----Original Message----- From: Jay Blanchard [mailto:jay.blanchard@niicommunications.com] Sent: Wednesday, November 03, 2004 9:12 PM To: Giles Roadnight; php-general@lists.php.net Subject: RE: [PHP] blank function parameters [snip] If I defined a function with 4 parameters but only pass 3 I get an error. Is there anyway around this? I want to be able to set the missing parameter to a default value if it is not passed which works ok but How do I get rid of the error message? [/snip] http://us2.php.net/manual/en/function.func-num-args.php "func_num_args() may be used in conjunction with func_get_arg() and func_get_args() to allow user-defined functions to accept variable-length argument lists. " -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ------------------------------------------------------------------------ -- Zareef Ahmed :: A PHP develoepr in Delhi ( India ) Homepage :: http://www.zasaifi.com