Re: help in php script
| From: | Deepak Dhake | Date: | Thu, 04 Nov 2004 15:33:08 +0000 |
| Subject: | Re: help in php script | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-201181@lists.php.net to get a copy of this message | ||
PRINT is nothing but...
TimeRotateImage.php
<?php
$curr_time = (localtime());
if ($curr_time[2] >= 6 and $curr_time[2] <= 17) {
print "<img src='image1.jpg'>";
}
else {
print "<img src='image2.jpg'>";
}
?>
this script (something like this) should be called from another script like,
<?PHP
print "<img src='TimeRotateImage.php'>";
?>
did you get what i am saying? please let me know if you have some solution.
thanks
Klaus Reimer wrote:
Deepak Dhake wrote:But i am not getting any output if i follow the above procedure. Can you tell me how to do it? I have to have the script TimeRotateImage.php which calculates which image to print accoring to local time and i want to embed the file name in html tag to print it on screen.It's not clear what your PRINT macros are doing. Maybe you forgot to send the content-type-header? Or maybe there is a script error which is not displayed when you call the page inside a image tag. Call the script directly in your browser to see what's going on. If it outputs binary data then everything is working but you forgot the content-type header.