Re: calling function from function?

Rick Fletcher wrote:

db( $defined[0], $defined[1], $defined[2], $defined[3] );

which tells me that the $db handle is not being returned when called from the db() function from within the logs() function and I am not sure why? it's being returned, you've just forgotten to assign it. add a "$db = " to the beginning of that line and you should be good to go. --Rick dang, thanks dude I knew it was something simple like that. just goes to show you how over analyzed things are. lol. thanks again.

-- Jason Gerfen jason.gerfen@scl.utah.edu "And remember... If the ladies don't find you handsome, they should at least find you handy..." ~The Red Green show