Re: Problem with parameter count in strstr()

Sorry, I was confusing strstr with strtr! "Matthew Weier O'Phinney" <matthew@garden.org> wrote in message news:slrncqpivq.sgk.matthew@webmaster.garden.org... >* Shaun <shaunthornburgh@hotmail.com>: >> I am trying to ensure that all data added to each element of >> $my_data_array >> has no commas, however I get an error message saying Warning: Wrong >> parameter count for strstr() >> >> $my_data_array[] = >> strstr( $data[1], ",", " " ); >> strstr( $data[2], ",", " " ).', '. >> strstr( $data[3], ",", " " ).', '. >> strstr( $data[6], ",", " " ).', '. >> strstr( $data[13], ",", " " ).', '. >> strstr( $data[14], ",", " " ).', '. >> strstr( $data[15], ",", " " ).', '. >> strstr( $data[16], ",", " " ).', '. >> strstr( $data[17], ",", " " ).', '. >> strstr( $data[18], ",", " " ).', '. >> strstr( $data[19], ",", " " ).', '. >> >> Could someone tell me what I am doing wrong here please? > > A couple things: > > * Syntax for strstr() is strstr(string $haystack, string $needle) -- > you're passing it three arguments instead of two > > * What exactly are you concatenating, and where do you expect it to go? > If you're trying to create a joined list of $data elements 1-19 and > assign it to a variable, you're going to run into issues when you get > to that semicolon at the end of your second line ;-) > > Also, if you're simply trying to do the following: > > * Join a list of elements with a , > * but only join the part of the element preceding a comma (or > space? not sure of your intentions as you've got bad arguments) > > Then you may want to try the following: > > function subStr($n) > { > return strstr($n, ','); > } > > $stripped = array_map('subStr', $data); > $my_data_array[] = join(', ', $stripped); > > > -- > Matthew Weier O'Phinney | > mailto:matthew@garden.org > Webmaster and IT Specialist | http://www.garden.org > National Gardening Association | > http://www.kidsgardening.com > 802-863-5251 x156 | > http://nationalgardenmonth.org