Re: creating an array in a while loop
| From: | hentis at twilyt dot com | Date: | Mon, 16 Oct 2000 12:42:49 +0000 |
| Subject: | Re: creating an array in a while loop | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-20358@lists.php.net to get a copy of this message | ||
I'm trying .. bvut not getting very far ..
this is basically the result i'mlooking for
while ($row=$this->db_fetch_array($result)){
$select_array[]="$row["lan"]=>$row["name"]";
}
I'm getting errors .. and I don't know arrays that well to know what I'm doing wrong
..
please help
henti
On Mon, Oct 16, 2000 at 12:34:49PM +0100, Clive Hughes wrote:
> Hentis,
>
> Do you mean you want to keep appending to the array(s)? If so, use empty
> square brackets, e.g.
>
> $myArray[] = "1";
> $myArray[] = "2";
> $myArray[] = "5";
>
> and so on. The example above creates $myArray with 3 elements ({1, 2, 5})
>
> --Clive
>
> ----- Original Message -----
> From: <hentis@twilyt.com>
> To: "PHP list" <php-general@lists.php.net>
> Sent: Monday, October 16, 2000 12:21 PM
> Subject: [PHP] creating an array in a while loop
>
>
> > hi all
> >
> > I've been trying to get around this for a while now .. but I seem to be
> stumped.
> >
> > I have a result from a query .. which I can fetch into an array as normal
> >
> > I want to creat an array with selected fields from the result. something
> like this.
> >
> > $result=mysql_query($query);
> > while ($row=mysql_fetch_array($result)){
> > $key=$row["element1"];
> > $value=$row["element2"];
> > $endarray[$key]=$value;
> > }
> >
> > I dont't knwo how to do this .. in code .. bu i have a general idea of
> creating an empty array with numrows as size
> > and then add each key/val pair in .. but I'm noot sure how to do it ..
> >
> > can somebody please lend a hand
> >
> > HEnti
> >
> >
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