RE: [PHP] null as function argumnent?

From: Date: Wed, 08 Dec 2004 20:23:48 +0000
Subject: RE: [PHP] null as function argumnent?
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-203760@lists.php.net to get a copy of this message
Bas Jobsen wrote: > Hi, > > I want to use a ?: statement. If not true de default function > argument have to be used. How to do this > > <? > function test($test='default') > { > echo $test; > } > test(($value==1)?'no default':null); >> > > What do i have to pass instead of null to get default print? Try this: function test($test = null) { if (is_null($test)) { $test = 'default'; } echo $test; } test(($value == 1) ? 'no default' : null);

« previous php.general (#203760) next »