RE: [PHP] grabbing source of a URL

Oops missed part of your question; > know what function to use to grab the page. for the string http://us2.php.net/manual/en/function.fopen.php There are some good samples on the page $dh = fopen("$url",'r'); $result = fread($dh,8192); Hope this is what you need. Warren Vail > -----Original Message----- > From: Adam Williams [mailto:awilliam@mdah.state.ms.us] > Sent: Friday, December 10, 2004 9:56 AM > To: php-general@lists.php.net > Subject: [PHP] grabbing source of a URL > > > Hi, I don't know what functions to use so maybe someone can > help me out. > I want to grab a URL's source (all the code from a link) and > then cut out > a block of text from it, throw it away, and then show the page. > > For example, if I have page.html with 3 lines: > > <html><head><title>hi</title></head> > <body> > <!-- line a --> > this is line a > <!-- end line a --> > <!-- line b --> > this is line b > <!-- end line b --> > <!-- line c --> > this is line c > <!-- end line c --> > </body></html> > > i want my php script to grab the source of page.html, strip out: > > <!-- line a --> > this is line a > <!-- end line a --> > > and then display what is left, how would I go about doing > this? I don't > know what function to use to grab the page. for the string > to remove, I > know I can probably do a str_replace and replace the known code with > nothing. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >