Re: formating output

print "<table>\n"; print "<tr>\n"; $counter = 0; while ($result = mysql_fetch_array($pointer)) {

    $counter++;
    if ($counter % 4 === 0) {
        print "<td>".$result[1]."</td>\n";
        print "</tr>\n";
        print "<tr>\n";
    } else {
        print "<td>".$result[1]."</td>\n";
    }

} // add blank cells if number of cell on last row isn'4 four. for ($i = 0; $i < $counter % 4; $i++) {

    print "<td>&nbsp;</td>\n";

} print "</tr>\n"; print "</table>\n"; --------------------------------- Larry L wrote:

I'm sure this is easy and I'll feel silly when I see how it's done, but, my mnd is a blank, this structure prints out a table with a new row for each item <table >

             <?
       While ( $results = mysql_fetch_array($pointer)) {
    print   "<tr><td ><$results[1] </td></tr>" ;
    }
    ?>
        </table>

what I want to do is print out a table 4 columns wide and however many rows high needed to run through the data HOW do I loop through the array and get <td>data</td> printed 4 times then a new row started and then 4 more <td> cells printed, etc thank you in advance